The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance between the ball in the room in a shot in which the ball goes exactly in the center of the room? Show your workThanks so much in advance ! :))

Answer:The distance between the ball in the room is [tex]4.2\ in[/tex]Step-by-step explanation:We know that for a circumference the radius is equal to half the diameter.[tex]r =\frac{d}{2}[/tex]The diameter of the basketball hoop is 18 inches.Then the radius of the hoop is:[tex]r = \frac{18}{2}\\\\r = 9\ inches[/tex]If, the circumference of the ball is 30 inches then the circumference C is:[tex]C = 2(\pi)r=30[/tex]And the radius of the ball is:[tex]30 = 2(\pi)r\\\\r =\frac{15}{\pi}[/tex]So the distance between the ball and the ring will be equal to the difference of both radius.[tex]k = 9-\frac{15}{\pi}\\\\k = 4.2\ in[/tex]